Math, asked by seharfatima4444, 4 months ago

The value of y in the given equation is

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Answered by Prashant3072005
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Answered by SweetMystery
28

Question :-

The value of y in the given equation is ???

Given Equation :-

 \frac{3y + 5}{2y + 1}  =  \frac{1}{3}

Answer :-

The value of y in the given equation is -2.

How to get it :-

 =  >  \frac{3y + 5}{2y + 1}  =  \frac{1}{3}

 =  > 3(3y + 5) = 1(2y + 1)

 =   > 9y + 15 = 2y + 1

 =  > 9y - 2y = 1 - 15

 =  > 7y =  - 14

  =  > y =  \frac{ - 14}{7}

.•.y =  - 2

" .•. " refers to therefore!

Points To Be Noted :-

The equation is solved by using the cross-multiplication method. After changing the places of the numerators(3y+5) and denominator(3), I solved the equation by using distributive property of multiplication. After that I brought the similar terms together and subtracted them. Finally I got the answer as -2.

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