Question

the value of y in the solution of 2^(x+y)=2^(x-y)=16 is.......


answer it clearly..

Answer 1

second pic is the alternative and easy method...... i hope this helps you solve the problem plz mark as brainliest

Answer 2

Solution:

It is given that,

$2^{x+y}=2^{x-y}=16$

i ) $2^{x+y} = 16$

=> $2^{x+y} = 2^{4}$

=> x+y = 4 ---(1)

/* If a^m = a^n then m = n */

Similarly ,

x-y = 4 ---(2)

Add (1) & (2) , we get

=> 2x = 8

=>x = 8/2

=>x = 4

Substitute x = 4 in equation (1),

we get

x + y = 4

=> 4 + y = 4

=> y = 0

Therefore,

x = 4 , y = 0

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