Question

the value of y in (y-5)^2=-16​

Answer 1

Answer:

Step-by-step explanation:

(y-5)^2=16

When we solve the bracket, we will get

y^2+(5)^2-2(y)(5)=16

y^2+25-10y=16

y^2-10y+25-16=0

y^2-10y+9=0

by discriminant method,

D=b^2-4ac

D=91

roots of the equation are,

10+$\sqrt{91$/2 and  10-$\sqrt{91$/2

so,value of y is 10+$\sqrt{91$/2or  10-$\sqrt{91$/2