Question

the value of y which satisfies the equation 5/2y+15 =40 and y +5=15​

Answer 1

Step-by-step explanation:

In the first equation, let us find value of y,

$\frac{5y}{2} = 40 - 15 \\ {5y} = 25 \times 2 \\ 5y = 50 \\ y = 10$

now adding this value of y in second equation our RHS should be equal to LHS

$y \ + 5 = 15 \\ value \: of \: y = 10 \\ 10 + 5 = 15$

Hence value of y which satisfied both equations is 10