Question

the value of (y)=y²-y+1for p(o) is..​

Answer 1

Answer:

p(0)=0^2-0+1=1

p(1)=1^2-1+1=1

p(2)=2^2-2+1=3

Step-by-step explanation:

Answer 2

Answer:

Step-by-step explanation:

P(0)

 $= 0^{2} - 0 + 1\\= 0 - 0 + 1\\= 0 + 1\\= 1$