Math, asked by tamseketan310, 16 days ago

The value of y2 = y(0.1) for the differential equation y'- 1 = y2,400) = 0,1-0,05
and with y(0.05)= y1 = 0.05 ​

Answers

Answered by araj3024
0

Answer:

The value of y2 = y(0.1) for the differential equation y'- 1 = y2,400) = 0,1-0,05

and with y(0.05)= y1 = 0.05

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