Question

The value (s) of k for which the quadratic equation
2x+ Kx+2=0 has equal root is​

Answer 1

Step-by-step explanation:

2x+Kx+2=0

2x+Kx+2=0b²-4ac=0 (given)

2x+Kx+2=0b²-4ac=0 (given)b=K

2x+Kx+2=0b²-4ac=0 (given)b=KA=2

2x+Kx+2=0b²-4ac=0 (given)b=KA=2C=2

2x+Kx+2=0b²-4ac=0 (given)b=KA=2C=2k²-4×2×2=0

2x+Kx+2=0b²-4ac=0 (given)b=KA=2C=2k²-4×2×2=0k²-16=0

2x+Kx+2=0b²-4ac=0 (given)b=KA=2C=2k²-4×2×2=0k²-16=0k²=16

2x+Kx+2=0b²-4ac=0 (given)b=KA=2C=2k²-4×2×2=0k²-16=0k²=16k=√16

2x+Kx+2=0b²-4ac=0 (given)b=KA=2C=2k²-4×2×2=0k²-16=0k²=16k=√16k=4

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