Question

The value(s) of p for which the quadratic equation: x² + p x + 16 = 0 has real and equal roots ​pls ans

Answer 1

Answer:

Real and equal roots then b²-4ac and=0

a=1

b=p

c=16

substitute

b²-4ac=0

p²-4(1)(16)=0

p²-64=0

p²=64

p=√64

p=+or-8

then p=8,-8

hope you understood

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