Question

The Value with the heb of logarithm 693.8÷532.4x2.405​

Answer 1

Answer:

Let x=5872×0.058

Taking log both sides, we have

logx=log(5872×0.058)

logx=log5872+log0.058(∵logab=loga+logb)

logx=log(58.72×10

2

)+log(58×0

−3

)

logx=log58.72+2+log58−3(∵log10=1)

⇒1+logx=log58.72+log58

Using log table, we get

log58.72=1.77

log58=1.76

∴1+logx=1.77+1.76

⇒logx=3.53−1

⇒logx=2.53

⇒x=Antilog(2.53)=338.84

Therefore,

5872×0.058≈338.84

Answer 2

Dude here is ur answer :-

The logarithmic function is an inverse of the exponential function. It is defined as:

y=logax, if and only if x=ay; for x>0, a>0, and a≠1.

Natural logarithmic function: The log function with base e is called natural logarithmic function and is denoted by loge.

f(x) = logex

The questions of logarithm could be solved based on the properties, given below:

Product rule: logb MN = logb M + logb N

Quotient rule: logb M/N = logb M – logb N

Power rule: logb Mp = P logb M

Zero Exponent Rule: loga 1 = 0

Change of Base Rule: logb (x) = ln x / ln b or logb (x) = log10 x / log10 b