Question

the value x is satisfying the equation log10x+log10(x-2) =3 is
​

Answer 1

Step-by-step explanation:

Given expression is valid when x>−1, x<1, x

2

<1

Therefore, x∈(−1,1)

But for x=0, L.H.S



=R.H.S

Thus x∈(−1,1)−{0}⇒(1)

log

10

1+x

+log

10

(

1−x

)+2log

10

(

1−x

)=log

10

1−x

2

+2

Answer 2

Step-by-step explanation:

refer to the attachment

it's Isha

drop some thx