Question

the values of 1+tan2 15^1-tan2 15 is

Answer 1

we know according to trigonometric function formula.

Answer 2

Answer:

$\frac{\sqrt{3}}{2}$

Step-by-step explanation:

In the given question,

We need to find the value of the given trigonometric equation,

$\frac{1+tan^{2}{15}}{1-tan^{2}15}$

Now,

We know from the identity of trigonometric functions that the given form of the equation,

$cos2\theta=\frac{1+tan^{2}\theta}{1-tan^{2}\theta}$

So, using the same we can say that,

On comparing we find out,

$\theta=15$

So,

On putting the value in the identity we can say,

$cos2(15)=\frac{1+tan^{2}15}{1-tan^{2}15}\\cos30=\frac{1+tan^{2}15}{1-tan^{2}15}\\\frac{1+tan^{2}15}{1-tan^{2}15}=\frac{\sqrt{3}}{2}$

Therefore,

The value of the term is given by,

$\frac{\sqrt{3}}{2}$