Question

The values of 3 ,5 & 7 are assigned weights as k-4, k-2 & k+1 respectively. If the weighted A.M is 6, then find k.​

Answer 1

Answer:

23/3

Step-by-step explanation:

A. M=sum of the weights/Total number of weights.

Given A. M=6

The weights are k-4, k-2 and k+1.

Therfore,

6=[(k-4)+(k-2)+(k+1)]/3

=(3k-5)/3

3k-5=6×3

=18

3k=18+5

=23

k=23/3

Answer 2

Concept:

The median is the middle value in the list of given numbers, sorted numerically from smallest to biggest, while the mode is the value of the number that appears in the list the most frequently. The mean is the average where the sum of all the numbers is divided by the total number of numbers.

Given:

The values of 3 ,5 & 7 are assigned weights as k-4, k-2 & k+1 respectively. If the weighted A.M is 6

Find:

find the value of k

Solution:

M=sum of the weights/Total number of weights.

Given A. M=6

The weights are k-4, k-2 and k+1.

Therefore,

6=[(k-4)+(k-2)+(k+1)]/3

⇒6=(3k-5)/3

⇒3k-5=6×3

⇒3k=18+5

        =23

⇒k=23/3

Therefore, the value of k=23/3

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