Question

The values of A (0°<A<360°) satisfying cosecA+2=0 are​

Answer 1

Answer:

A=210°,330°

Step-by-step explanation:

Given, cosecA+2=0

or, sin A=-1/2

or, A =(π+π/6),(2π-π/6)

or A=7π/6,11π/6

So, A= (7*180°)/6=210°,  (11*180°)/6=330°

I hope it can help you