Question

the values of and y' are s values of x and y' which satisfy near equation x + 3y = 10 are
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Answer 1

Step-by-step explanation:

x+3y=10

Subtract x from both sides.

3y=10-x

Divide both sides by 3.

$\frac{3y}{3}=\frac{10-x}{3}$

$y=\frac{10-x}{3}$

x=10-3y