Question

The values of electronegativity of atoms A and B are 1.20 and 4.0 respectively. The percentage of ionic character of A - B bond is
(a) 50%
(b) 72.24%
(c) 55.3%
(d) 43%

Answer 1

Answer:

Correct option is

B

72.2%

explanation :-

Ionic character can be calculated by formula :

% ionic charcter = 16[E

A

−E

B

]+3.5[E

A

−E

B

]

2

% ionic character = 16[4−1.2]+3.5[4−1.2]

2

% ionic character = 72.24