Question

The values of ∂f/(∂x )and ∂f/(∂y )at the point (4,-5)of the function f(x,y)=x^2+3xy+y-1 are:

Answer 1

Step-by-step explanation:

We have,

$f(x,y) = x^{2} + 3xy + y -1$

Now,

$\frac{ \delta f}{ \delta x} = 2x + 3y$

$\implies \frac{ \delta f}{ \delta x} _{(4 , - 5)} = - 7$

$\implies \frac{ \delta f}{ \delta y} = 3x + 1$

$\implies \frac{ \delta f}{ \delta y} _{(4 , - 5)} = 13$