Question

The values of ∆H for the combustion of ethane and acetylene
are –341.1 and –310.0 kcal, respectively. The better fuel is :
(a) ethane (b) acetylene
(c) both (d) none of these

Answer 1

Ethyne is bettter gas welder.

Correct option is (D).

Explanation:

A better gas welder is one which possesses high calorific value i.e., heat produced by 1 g of fuel.

Calorific value for ethane = (−341.1 / 30)

= −11.37 kcal/g (mol.Wt.= 30)

Calorific value for ethyne = (−310.0/26) ltbr. = −11.92 kcal / g (mol.wt. = 26)

Thus ethyne is bettter gas welder.

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Answer 2

The better fuel is acetylene.

Step by step explanation:

From the given,

The combustion value of ethane = -341.1 kcal

Molarmass of ethane = 28 g/mol

               $\bold{Calorific\,value=\frac{\Delta\,H}{Molar\,mass}}$

          $Calorific\,value=\frac{-341.1}{28}=-12.1kcal/g$

The combustion value of aetylene = -310.0 kcal

Molarmass of acetylene = 26 g/mol

               $\bold{Calorific\,value=\frac{\Delta\,H}{Molar\,mass}}$

          $Calorific\,value=\frac{-310.0}{26}=-11.92kcal/g$

Less calorific value fuel has high efficiency.

Therefore, The better fuel is acetylene.

Hence, correct option is "b".

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