Math, asked by rneharawat04, 7 months ago

The values of k for which k x^2 - 4 x - 1 can be factorized into real linear factors, are
k < 4
k ≥ -4
k ≤ -6
k < -4

Answers

Answered by Anonymous
2

Answer:

option 2 is the ans mate

Step-by-step explanation:

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Answered by mysticd
0

 Compare \: given \: Quadratic \: polynomial

 kx^{2}-4x-1 \:with \: ax^{2} + bx + c , we \:get

 a = k , b = -4 \:and \:c = -1

 Discreminant (D) \geq 0

 \blue{ ( Given , roots \:are \:real ) }

 \implies (-4)^{2} - 4 \times k \times (-1) \geq 0

 \implies 16+4k \geq 0

 \implies 4k \geq -16

 \implies k \geq \frac{-16}{4}

 \implies k \geq -4

Therefore.

 Option \: \pink{(b)} \:is \: correct

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