Question

the values of k for which the quadratic equation 2x2 +Kx +2=0 has equal roots is​

Answer 1

The values of k = 4.

Given:

Quadratic equation $2x^{2}+Kx +2=0$ has equal roots.

To find:

The values of k

Explanation:

General format of quadratic equation is $ax^2+bx+c =0$.

If the roots of quadratic equation is equal then,        

$\sqrt{b^{2} \ -\ 4ac }=0$

Where,                                                

a =  coefficient of x²  

b = coefficient of x                                            

c = constant term.          

$\sqrt{b^{2} \ -\ 4ac }=0$      

b² - 4ac =0

Comparing the quadratic equation

$2x^{2}+Kx +2=0$        

b = k    a=2    c=2                  

k² - 4×2×2 = 0                        

k² = 16    

k = $\sqrt{16}$                        

k = 4

Therefore, the values of k = 4 if roots are equal.

To learn more...

1. If alpha and beta are roots of quadratic equation 3x2+kx+8 and alpha/beta=2/3 then find the value of k​

brainly.in/question/14068687

2. The sum of the roots of a quadratic equation is 3 while the sum of the squares of its roots is 7. find the equation.

brainly.in/question/4888783

Answer 2

If the roots of any equation are equal then it means that their Discriminant = 0

So, b²-4ac = 0

We have given the equation 2x² + kx + 2, where,

a = 2

b = k (we have to find the value)

c = 2

Then, b²-4ac=0

b² - 4(2)(2) = 0

b² - 16 = 0

b² = 16

√16 = 4

Hence the vue of k is 4.

:-) Hope it helps