Math, asked by chaudharyshreyarathi, 7 days ago

the values of k for which the system of equation x+3y+1=0 and 4x +ky + 7 =0 has no solution is ​

Answers

Answered by akshatguntewar
0

Answer:

12

Step-by-step explanation:

if equation has no solution then, a1/a2 = b1/b2 ≠ c1/c2

a1=1

a2=4

therefore a1/a2= 1/4

b1 = 3

b2 =k

1/4=3/k

after cross multiplication we get,

k=12

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