the values of k such that the roots of equation kx^2-4x+2=0 real
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Answered by
0
Answer:
It is given that, roots of the quadratic equation is real & equal
∴ b²-4ac
∴ Comparing kx² - 4x + 2 with ax²+bx+c = 0
∴ a = k
b = -4
c = 2
∴ b² - 4ac = (-4)² -4 * k * 2 = 0
= 16 - 8k = 0
= 16 = 8k
= k = 16/8
= k = 2
∴ The value of the k in the given equation is 2
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Answered by
1
Answer:
quadratic equation kx
2
+4x+1=0, has real and distinct roots
To find the value of k
Sol: An equation has real and distinct roots if the discriminant b
2
−4ac>0
In the given equation, a=k,b=4,c=1
Therefore the discriminant is 4
2
−4(k)(1)>0
16−4k>0
⟹4k<16
Therefore, k<4
Explanation:
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