Question

The values of quantum numbers n, land m for the 5th electron
of boron will be
(a) n=1,1= 0, m =-1
(c) n=2,1= 2, m=-1
(b) n=2,1=1, m=-1
(d) n=1,1=2, m=-1​

Answer 1

Electronic configuration of boron

1 s ² 2 s² 2 p ¹

From this u can see that the last (5 th) electron enters the p orbital

2 p ¹

Here ,

n = 2

value of l for p is 1

l = 1

If value of l is 1 then the value of m can be anything between - 1 and + 1

spin can be +1/2 or - 1/2

According to the given options b is correct

Answer 2

Explanation:

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