Question

The values of resistance and resistivity of 0.2 N
solution of H2SO4, are 50ohm and 77ohm c
respectively. The molar conductivity of the solution
is
(1) 50 S cm2mol-1 (2) 158 S cm2-mol-1
(3) 105 S cm 2mol (4) 130 S cm2-mol-1​

Answer 1

Answer:129.8~130

Explanation:

^m=k×1000/c

c=.2/2=.1

k=1/77

put all value in above equation.

so molarconductivity will be 130 approx

Answer 2

The molar conductivity of the solution =130$S cm^2-mol^{-1}$

Explanation:

Resistance of solution=500 ohm

Resistivity of solution=$\rho$=77 ohm-cm

Conductivity of solution=$\kappa=\frac{1}{\rho}$

$\kappa=\frac{1}{77}$ per ohm per cm

Normality of solution=0.2N

Molarity of solution=$\frac{N}{number\;of \;hydrogen}$

We have number of hydrogen=2

Molarity of solution=$\frac{0.2}{2}=0.1M$

Molar conductivity of solution=$\Lambda_M=\frac{1000\times \kappa}{C}$

Where C=Concentration of solution(in M,mol per L)

$\kappa$=Conductivity of electrolyte

Substitute the values

Molar conductivity of solution=$\frac{1000\times \frac{1}{77}}{0.1}$

Molar conductivity of solution=130$S cm^2-mol^{-1}$

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