the values of tan theta from the equ 3 (sec square theta -1)+16tan theta+5=0are
Answers
Answered by
2
check the attachment
Attachments:
Answered by
0
3(sec^2 x - 1) + 16tanx + 5 = 0
We know, 1 + tan^2 x = sec^2 x
3tan^2 x + 16tanx + 5= 0
Let tanx = a
3a^2 + 16a + 5 = 0
3a^2 + 15a + a + 5 = 0
(a+5) (3a+1) = 0
a = -5, -1/3
=> -5 does not come in the range of the value of function tanx
=> tanx = -1/3
Hope this helps... plsss make it the brainliest
We know, 1 + tan^2 x = sec^2 x
3tan^2 x + 16tanx + 5= 0
Let tanx = a
3a^2 + 16a + 5 = 0
3a^2 + 15a + a + 5 = 0
(a+5) (3a+1) = 0
a = -5, -1/3
=> -5 does not come in the range of the value of function tanx
=> tanx = -1/3
Hope this helps... plsss make it the brainliest
Similar questions