Chemistry, asked by akhilvinayak03, 10 months ago

The values of TC of a few gases are given below. H2 = 33.2 K, O2 = 154.3K,He= 5.3K and CO2 = 304.10K. What is the correct order of liquefaction of the above gases when cooled from 400K ?
1) He, O2, H2, CO2
2) CO2, O2, H2, He
3) He, H2, O2, CO2
4) O2, CO2, H2, He

Answers

Answered by Fatimakincsem
1

Correct order of liquefication is CO2 > O2 > He > H

Explanation:

The molecules or compounds which have  the heavier molecular weight they get liquefied  firstly.

Molecular wt of H  2 = 2

Molecular wt of He = 4

Molecular wt of O2 = 16

Molecular wt of CO2 = 44

The correct order is

CO2 > O2 > He > H

Thus CO2 has the highest tendency to get liquefied and Hydrogen has the least.

Answered by Anonymous
0

Answer :-

Correct order of liquefication is CO2 > O2 > He > H

Explanation:

The molecules or compounds which have  the heavier molecular weight they get liquefied  firstly.

Molecular wt of H  2 = 2

Molecular wt of He = 4

Molecular wt of O2 = 16

Molecular wt of CO2 = 44

The correct order is

CO2 > O2 > He > H

Thus CO2 has the highest tendency to get liquefied and Hydrogen has the least.

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