the values of two resistors are r=6+_0.3 and r =10+_0.2.the percentage error in the equivalent resistence when they are connected in parallel is
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R= R1*R2/R1+R2,
where R is equivalent resistance %error in
R = % error in R1*R2 +%error in R1+R2 %error in R1*R2 =%error in R1 + %error R2 %error in
R1= 0.3/6*100= 5%%
error in R2 = 0.2/10 * 100 = 2%%
error in R1+ R2= 5%+2% =7%%
error in R1 +R2 = 0.3+0.2/16 *100 = 3.125%
Total error in R = 7%+3.125% =10.125%
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