Physics, asked by asthasinghhh, 1 year ago

the values of two resistors are r=6+_0.3 and r =10+_0.2.the percentage error in the equivalent resistence when they are connected in parallel is


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Answers

Answered by Shivaya1
9

R= R1*R2/R1+R2,

where R is equivalent resistance %error in

R = % error in R1*R2 +%error in R1+R2 %error in R1*R2 =%error in R1 + %error R2 %error in

R1= 0.3/6*100= 5%%

error in R2 = 0.2/10 * 100 = 2%%

error in R1+ R2= 5%+2% =7%%

error in R1 +R2 = 0.3+0.2/16 *100 = 3.125%

Total error in R = 7%+3.125% =10.125%

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