Question

The values of two resistors are R1 = (6 + 0.3) kN and R2
= (12 + 0.3) ko. If they are connected in parallel, then
the equivalent resistance Reg of the combination will
1 1
be
Roo R, R₂
II
+
eg

Answer 1

Answer:

When the two resistors are connected in parallel, the equivalent resistance will be

R

P

=

R

1

+R

2

R

1

R

2

Differentiating both sides ,

R

P

ΔR

P

=

R

1

ΔR

1

+

R

2

ΔR

2

+

R

1

+R

2

Δ(R

1

+R

2

)

R

P

ΔR

P

=

6

0.3

+

10

0.2

+

16

0.3+0.2

=0.05+0.02+0.03125=0.10125

% error =

R

P

ΔR

P

×100=0.10125×100=10.125%

Answer 2

Answer:

R

eq

=

36

0.3

+

144

0.3

=16(

36

0.3

+

144

0.4

)

= 0.133+0.033

= 0.1663

R=4±0.1663

• ( 4 + 0.1 ) kQ

Explanation:

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