Question

The values of x and y satifying the equations x/2 +y/3=2 ,x + 2y = 8 are given by the pair

Answer 1

Step-by-step explanation:

here is the answer brother

Answer 2

GIVEN :-

» x/2 + y/3 = 2

➡ 3x/6 + 2y/6 = 2 (took LCM of 2 and 3)

➡ 3x + 2y = 12 ------(i)

» x + 2y = 8 ------(ii)

Using substitution method,

From equation (i), we get

➡ 3x = 12 - 2y

➡ x = (12 - 2y)/3

Putting value of x = (12 - 2y)/3 in equation (ii)

➡ (12 - 2y)/3 + 2y = 8

➡ (12 - 2y)/3 + 6y/3 = 8

➡ 12 - 2y + 6y = 8 × 3

➡ 12 + 4y = 24

➡ 4y = 24 - 12

➡ 4y = 12

➡ y = 12/4

➡ y = 3

Now putting value of y = 3 in equation (i)

➡ 3x + 2(3) = 12

➡ 3x = 12 - 6

➡ x = 6/3

➡ x = 2

Hence, the value of x = 2 and y = 3

VERIFICATION :-

For equation (i),

LHS :-

= 2/2 + 3/3

= 1 + 1

RHS :-

= 1

LHS = RHS. hence verified!

For equation (ii),

LHS :-

= 2 + 2(3)

= 2 + 6

= 8

RHS :-

= 8

LHS = RHS. hence verified!

So the value of x and y must be 2 and 3 respectively.