Question

The values of x and y when a point lies on the linear equations 2x-3y =12

Answer 1

three possible values of (x , y) are (0, - 4) , (6, 0) and (3, -2) .

Step-by-step explanation:

Given :- The value of x and y when a point lies on the linear equation 2x - 3y = 12 .

Solution :-

when x = 0

→ 2 * 0 - 3y = 12

→ (-3y) = 12

→ y = (-4) .

when y = 0

→ 2x - 3 * 0 = 12

→ 2x = 12

→ x = 6

when x = 3

→ 2*3 - 3y = 12

→ 6 - 3y = 12

→ (-3y) = 12 - 6

→ (-3y) = 6

→ y = 6/(-3)

→ y = (-2)

so, three possible values of (x , y) are (0, - 4) , (6, 0) and (3, -2) .

Answer 2

Given: the value of x and y when a point lies on the linear equation 2x-3y=12

Solution:-

When x =0
2*0-3y=12
Y=(-4)

When u=0
2x-3*0=12
2x=12
x = 6


When x=3
2*3 -3y=12
6-3y=12
(-3y)=12-6
(-3y)=6
Y=6/(-3)
Y=(-2)

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