Math, asked by udithpudith, 5 hours ago

The values of ‘x’ and ‘y’ when a point lies on the linear equation 2x - 3y = 12 A. x = 0, y = -3 B. x = 2, y = 3 C. x = 3, y = -2 4. D. x = -2, y = +3​

Answers

Answered by uayush232
0

I DONT YOUR ANSWERS PLEASE

Answered by amitnrw
0

Given :

 a point lies on the linear equation 2x-3y=12

To Find : The value of 'x' and 'y'

A. x = 0, y = -3

B. x = 2, y = 3

C. x = 3, y = -2

D. x = -2, y = 3

Solution:

2x-3y=12

x = 0

=> 2(0) - 3y = 12

=> y = - 4

Hence  x = 0, y = -3     is incorrect

2x-3y=12

x = 2

=> 2(2) - 3y = 12

=> -3y = 8

=> y = - 8/3

Hence  x = 2, y =  3     is incorrect

2x-3y=12

x = 3

=> 2(3) - 3y = 12

=> -3y =  6

=> y = - 2

Hence  x = 3  y = -2    is correct

2x-3y=12

x = -2

=> 2(-2) - 3y = 12

=> -3y = 16

=> y = - 16/3

Hence  x = -2, y =  3     is incorrect

so point is         x = 3  y = -2

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