The values of ‘x’ and ‘y’ when a point lies on the linear equation 2x - 3y = 12 A. x = 0, y = -3 B. x = 2, y = 3 C. x = 3, y = -2 4. D. x = -2, y = +3
Answers
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Given :
a point lies on the linear equation 2x-3y=12
To Find : The value of 'x' and 'y'
A. x = 0, y = -3
B. x = 2, y = 3
C. x = 3, y = -2
D. x = -2, y = 3
Solution:
2x-3y=12
x = 0
=> 2(0) - 3y = 12
=> y = - 4
Hence x = 0, y = -3 is incorrect
2x-3y=12
x = 2
=> 2(2) - 3y = 12
=> -3y = 8
=> y = - 8/3
Hence x = 2, y = 3 is incorrect
2x-3y=12
x = 3
=> 2(3) - 3y = 12
=> -3y = 6
=> y = - 2
Hence x = 3 y = -2 is correct
2x-3y=12
x = -2
=> 2(-2) - 3y = 12
=> -3y = 16
=> y = - 16/3
Hence x = -2, y = 3 is incorrect
so point is x = 3 y = -2
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