Question

the values of x and y when a point lies on the linear equation 2x-3y=12​

Answer 1

Step-by-step explanation:

The value of x and y when a point lies on the linear equation 2x - 3y = 12 . → y = (-4) . so, three possible values of (x , y) are (0, - 4), (6, 0) and (3, -2) . There will be infinite number of solutions

Answer 2

$\large\blue{\textsf{✩ Answer ✓ }}$

The given equation

2x-3y = 12

contains two unknown quantities x, y and the constant 12. To express y in terms of x, we need to isolate y by taking it to one side and the remaining two terms to the other side. Thus taking -3y from left-side to right-side and 12 from right to left,

2x - 12 = 3y

Or, 3y = 2x - 12 (∵ a = b ⇒ b = a )

Dividing both sides by 3,

3y/3 = (2x-12)/3 = 2x/3 -12/3

Or, 1.y = 2x/3 - 4

⇒ y = (2x/3) - 4 …………………………………………………………..……………(1)

which is the required equation that expresses y in terms of x explicitly.

The relation (1) shows that for every value we choose to give to x, there will be one corresponding value of y. Thus we can find as many pairs of values as we please which satisfy the given equation (1). The solution pairs is infinite. For purposes of illustration, we give below results for five different values of x:

when x has the values 3, 2, 0, -1, -2

we get for y the values -2 -8/3 -4 -14/3 -16/3