The values of x for the equation x2 + 9x+ 18 = 6 - 4xare
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x*2 − 9x + 18
= x*2− 6x − 3x + 18
=x*2− 6x − 3x + 3 × 6
=x(x−6)−3(x−6)
=(x−3)(x−6)
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X^2+9x+4x+18-6=0
x^2+13x+12=0
(×+1)(×+12)=0
×=-1 ,×=-12
x^2+13x+12=0
(×+1)(×+12)=0
×=-1 ,×=-12
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