the values of x in(3x+1)(x-1)=(5x-3)(2x-3)
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3x+1x-1=5x6x-3
-2x=-4
x=-4÷-2
x=2
-2x=-4
x=-4÷-2
x=2
kanishkkandee:
wrong
there are 2 answers
Answered by
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Hay Mate
Let's Solve,
(3x+1)(x-1) = (5x-3)(2x-3)
=> 3x²-3x+x-1 = 10x²-15x-6x+9
=> 3x²-10x²-3x+15x+x+6x = 9+1
=> -7x²+12x+7x = 10
=> -7x²+19x = 10
=> 7x²-19x+10 = 0
=> 7x²-14x-5x +10 = 0
=> 7x(x-2) -5(x-2) =0
=> (7x-5) (x-2) = 0
(7x-5) = 0
7x-5 = 0
7x = 5
x = 5/7
or,
(x-2) =0
x -2 =0
x = 2
I hope it's help you
Let's Solve,
(3x+1)(x-1) = (5x-3)(2x-3)
=> 3x²-3x+x-1 = 10x²-15x-6x+9
=> 3x²-10x²-3x+15x+x+6x = 9+1
=> -7x²+12x+7x = 10
=> -7x²+19x = 10
=> 7x²-19x+10 = 0
=> 7x²-14x-5x +10 = 0
=> 7x(x-2) -5(x-2) =0
=> (7x-5) (x-2) = 0
(7x-5) = 0
7x-5 = 0
7x = 5
x = 5/7
or,
(x-2) =0
x -2 =0
x = 2
I hope it's help you
sorry mate
mate can you answer my another question
Sorry I didn't better in physics
have you any math questions
no it's maths only
OK I will see
I just posted 2
soon
hello r u there
plz help
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