Question

the valve of 'k' so that the following system of equations 3x-y-5=0 ,6x-2y+k=0​

Answer 1

Answer:

Step-by-step explanation:

3x-y-5=0

so 3x-y=5 (1st equation)

now multiply the equation by 2

(3x-y=5)×2

= 6x-2y=10

but as per the question

6x-2y-p=0

6x-2y=p

substitute the equations

p=10