Chemistry, asked by Gahqhwnwjvsb531, 1 year ago

The van der waals excluded volume b = 0, 0.2 and 0.4 corresponds to benzyne gases

Answers

Answered by jacobcunningham202
1

DOI: 10.1007/s10910-007-9272-4

Journal of Mathematical Chemistry, Vol. 43, No. 4, May 2008 (© 2007)

The van der Waals equation: analytical and approximate

solutions

Mario N. Berberan-Santos

Centro de Qu

́

ımica-Fısica Molecular, Instituto Superior Tecnico, Lisboa P-1049-001, Portugal

E-mail: [email protected]

Evgeny N. Bodunov

Department of Physics, Petersburg State Transport University, St. Petersburg 190031, Russia

E-mail: [email protected]

Lionello Pogliani

Dipartimento di Chimica, Universit

`

a della Calabria, via P. Bucci, 14/C, Rende CS I-87036, Italy

E-mail: [email protected]

Received 8 February 2007; Revised 23 February 2007

The thermodynamic properties, enthalpy of vaporization, entropy, Helmholtz func-

tion, Gibbs function, but especially the heat capacity at constant volume of a

van der Waals gas (and liquid) at the phase transition are examined in two different

limit approximations. The first limit approximation is at the near-critical temperatures,

i.e., for

T/T

c

1, where

T

c

is the critical temperature, the other limit approximation

is at the near-zero temperatures,

T

0. In these limits, the analytical equations for

liquid and gas concentrations at saturated conditions were obtained. Although the heat

capacities at constant volume of a van der Waals gas and liquid do not depend on the

volume, they have different values and their change during the phase transition was cal-

culated. It should be noticed that for real substances the equations obtained at the near-

zero temperature are only valid for

T>T

triple point

and

T

T

c

, which means that

found equations can be used only for substances with

T

triple point

T

c

.

KEY WORDS:

thermodynamics,  van  der  Waals  equation,  phase  transition,

heat capacities, critical temperature

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