Chemistry, asked by abhijeetjha3279, 1 year ago

The van't hoff factor i for a 0.2 molal aqueous solution of urea is

Answers

Answered by gadakhsanket
56
Hey mate,

● Answer-
i = 1

● Explaination-
- Van't hoff factor is defined as ratio of no of molecules after dissociation (association) to no of molecules before dissociation (association).
i = N(after) / N(before)

- As urea is a non-electrolyte it doesn't dissociative into aqueous solution.
- As N(after) = N(before), value of i = 1.

Hope this helps you...
Answered by mirakrishnabaskar
1

Answer:

________ i = 1 ________

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