Question

the van,t Hoff,s factor of .01mba(No2)2 solution is 2.74.the degree of discussion is

Answer 1

In case of association i (van’t Hoff factor) is given by
i = 1 – (1- 1/n)α, where
n= number of molecules associates = 4 (here),
α = fraction of molecules associates

i = 1 – (1- ¼)α = 1 – ¾ α
if α be 1 (complete association), then

i= 1 – ¾ = ¼

Answer 2

Answer :0.870.87

α=i−1(x+y)−1=2.74−13−1α=i−1(x+y)−1=2.74−13−1=0.87