the vant hoff factor for a 0.1M Al2(SO4)3 solution is 4.20.the degree of disssociation is?
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Answered by
37
Alpha = 1-i / 1-n
1-4.20/ 1-5. (5 ions after dissociation)
Alpha= 0.80
1-4.20/ 1-5. (5 ions after dissociation)
Alpha= 0.80
Answered by
46
Answer: The degree of dissociation is 80%
Explanation:
Vant hoff factor is the ratio of observed colligative property to the calculated colligative property.
0.1 0 0
Total moles after dissociation =
thus
Thus degree of dissociation is 80%.
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