The vapor pressure of a pure substance is measured to be 812mmHg at a specific temperature. A non-volatile solute is added to this substance and the vapor pressure is measured to be 400mmHg. What is the mole fraction of the non- volatile solute
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Answer:
According to Raoult's law,
P
0
P
0
−P
s
=
n+N
n
Let m be the molecular mass of the solid substance.
n=
m
2.175
;N=
78
39
=0.5
(molecular mass of benzene = 78)
P
0
=640mm;P
s
=600mm
Substituting the values in above equation,
640
640−600
=
m
2.175
+0.5
m
2.175
=
2.175+0.5m
2.175
m=
0.5
2.175×16−2.175
=65.25
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