Question

The vapor pressure of benzene is expressed by the following formula:
3884 K
In(P/toit) = - = +17.63
Calculate the boiling temperature of benzene wlien the atmospheric pressure is 500 torr.
(A) 340.2 K
(B) 34.2 K
(C) 273.15 K
(D) 278.15 K​

Answer 1

Given that,

Atmospheric pressure = 500 torr

We need to calculate the boiling temperature

Using given formula

$ln(P)=\dfrac{-3884}{T}+17.63$

Where, P = pressure

T = temperature

Put the value into the formula

$ln(500)=\dfrac{-3884}{T}+17.63$

$\dfrac{-3884}{T}=6.21-17.63$

$\dfrac{-3884}{T}=-11.42$

$T=\dfrac{3884}{11.42}$

$T=340.2\ K$

Hence, The boiling temperature is 340.2 K

(A) is correct option.