Question

The vapor pressure of two pure liquids A and B that form an ideal solution are 100 and 900 torr respectively at temp T. This liquid solution of A and B is composed of 1 mole of A and 1 mole of B. what will be the pressure if 1.5 moles of liquid mixture has been vaporized.

Answer 1

Pa* =vapour pressure of pure liquid A = 100 torr

Pb*=vapour pressure of pure liquid B = 900 torr

As we know that,

Ps = Pa*+(Pb*-Pa*)xb

here,Ps = vapour pressure of solution

Xb = mole fraction of volatile solute

So, Ps = 100+(900-100)×0.5(here,xb = number of moles of solute/ total number of moles of solution = 1/1+1= 0.5 moles)

Ps = 500 torr

Ans. 500 torr

Answer 2

Answer:

300 torr

Explanation:

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