The vapour density of a certain gas X is 4 times that of Y. The molecular mass of X is M the molecular mass of Y is
a)4M
b)0.5M
c)0.25M
d)0.33M
Answers
Answered by
3
Molecular mass = 2×vapour density
From this relation,
Your answer is (c).
Answered by
3
We know that vapour density of any gas = molecular mass divided by the mass of Hydrogen gas (2)
or vapour density = half of the molecular mass
Then as given
vapour density of X = 4 times vapour density of Y
Mass of X = M
Vapour density of X = M/2 = 0.5 M
now from above
0.5M = 4Y
=> Y = 0.125M
or vapour density of Y = 0.125 M
therefore mass of Y = 0.125M× 2
= 0.250 M
or 0.25 M
Answer = option "c"
Hope it helps you
or vapour density = half of the molecular mass
Then as given
vapour density of X = 4 times vapour density of Y
Mass of X = M
Vapour density of X = M/2 = 0.5 M
now from above
0.5M = 4Y
=> Y = 0.125M
or vapour density of Y = 0.125 M
therefore mass of Y = 0.125M× 2
= 0.250 M
or 0.25 M
Answer = option "c"
Hope it helps you
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