Question

the vapour density of a compound is 45 it's molecular formula will be!?

Answer 1

Answer:

We assume a mass of 100⋅g of compound...and thus. ... the vapour density of this material as 45 ..and this is relative to ... The molecular formula≡C4H8O2 ...this question seems ...

Answer 2

The question is incomplete, here is the complete question:

The empirical formula of a compound is $CH_2O$ . if it's vapour density is 45, the molecular formula will be?

The molecular formula for the given organic compound is $C_3H_6O_3$

Explanation:

To calculate the molecular mass, we use the equation:

[tex]\text{Molecular mass}=2\times \text{Vapor density} [/tex]

We are given:  

Vapor density = 45  

Putting all the values in above equation, we get:  

$\text{Molecular mass}=2\times 45=90g/mol$

The given empirical formula of the compound is $CH_2O$

For determining the molecular formula, we need to determine the valency which is multiplied by each element to get the molecular formula.

The equation used to calculate the valency is:

$n=\frac{\text{Molecular mass}}{\text{Empirical mass}}$

We are given:

Mass of molecular formula = 90 g/mol

Mass of empirical formula = 30 g/mol

Putting values in above equation, we get:

$n=\frac{90g/mol}{30g/mol}=3$

Multiplying this valency by the subscript of every element of empirical formula, we get:

$C_{(1\times 3)}H_{(2\times 3)}O_{(1\times 3)}=C_3H_6O_3$

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