Question

the vapour density of a gas is 11.2 .calculate the volume occupied by 11.2g of the has at NTP

Answer 1

Molecular mass=2*vapour density
=2*11.2
=22.4 g
At NTP,
volume occupied by 22.4 g of gas= 22.4 l
volume of 11.2g gas = 22.4/22.4*11.2
= 11.2 l

Answer 2

Answer : The volume occupied by 11.2 g of the gas at NTP is, 11.2 L

Solution :

First we have to calculate the molecular mass of gas.

$\text{Molecular mass}=2\times \text{Vapor density}=2\times 11.2=22.4g/mole$

Now we have to calculate the volume of gas.

As we know that 1 mole of gas contains 22.4 L volume of gas

And 1 mole of gas is equal to 22.4 g

As, 22.4 g of gas present in 22.4 L volume of gas

So, 11.2 g of gas present in $\frac{22.4}{22.4}\times 11.2=11.2L$ volume of gas

Therefore, the volume occupied by 11.2 g of the gas at NTP is, 11.2 L