the vapour density of a gas is 11.2.the volume occupied by 11.2g of the gas at STP will be
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if the vapour density is 11.2
molecular mass=2*vapour density
molecular mass=2*11.2=22.4 g
11.2g=11.2/22.4 mole=0.5 mole
1 mole occupies=22.4 lit.
0.5 mole occupies=22.4*0.5=11.2 lit.
molecular mass=2*vapour density
molecular mass=2*11.2=22.4 g
11.2g=11.2/22.4 mole=0.5 mole
1 mole occupies=22.4 lit.
0.5 mole occupies=22.4*0.5=11.2 lit.
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3
Answer:
2Lit.
Explanation:
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