Question

The vapour density of a gas is 11.2, then 11.2 g of this gas at N.T.P. will occupy a volume-
(a) 11.2 L
(b) 22.4 L
(c) 11.2 mL
(d) 22.4 mL

Answer 1

Molecular mass of the gas = 2× Vapour density of the gas

Molecular Mass = 2×11.2=22.4g/m

22.4 g of the gas = 1 mole of the gas

11.2 g of the gas = (1×11.2)22.4 = 0.5 mole of gas

22.4 L of gas = 1 mole of gas

∴ 0.5 mole of gas = (22.4×0.5) = 11.2 L of gas

ANSWER IS a) 11.2 L