Question

The. vapour density of a gaseous element is 5 times that of oxygen under similar conditions . If the molecule is triatomic, what will be d atomic mass

Answer 1

Answer: The atomic mass of the gas is 53.33 g/mol.

Explanation:

Molar mass = 2 × Vapor density

Vapor density of the oxygen gas = v

Molecular mass of oxygen = 2 × Vapor density of oxygen

Vapor density of the oxygen gas:

$v=\frac{32 g/mol}{2}=16$

The. vapour density of a gaseous element is 5 times that of oxygen under similar conditions.

The vapor density of the gaseous element =

5 × Vapor density of oxygen =  5 × 16 = 80

Let the atomic mas of the gaseous element be x g/mol.

Molecular mass of triatomic gas  = 2 × Vapor density of the gas

$3\times x=2\times 80$

$x=53.33 g/mol$

The atomic mass of the gas is 53.33g/mol.

Answer 2

Ratio Of Formic Acid To Oxalic Acid = 4:1

Given:

The Molecular Mass of Oxygen = 32 u

Calculating Density Of Oxygen:

= 32 / 2 = 16 u

Molecular mass of a gaseous element

=  80 * 2 = 160 u

Atomicity of the element = 3

Calculating the Atomic Mass of the element:

Formula Used = $\frac{Molecular Mass}{Atomicity}$

= 160 / 3 = 53.33 u

Which is 1 / 6 th of its volume because equal volume of gasses have equal number of moles according to the Avogrado's Law.

Therefore, $\frac{MolesOfCO2}{MolesOfBothGases}$

=> $\frac{x}{2x + y}$ = 1 / 6

=> 6x = 2x + y

=> 6x - 2x = y

=> 4x = y

=> y / x = 4

Therefore, the molar formula of formic acid to oxalic acid = 4 : 1.