The. vapour density of a gaseous element is 5 times that of oxygen under similar conditions . If the molecule is triatomic, what will be d atomic mass
Answers
Answered by
2
Let’s consider d as density, M as molecular mass therefore
For oxygen, d/M = d(oxygen)/32 ---(1)
(Oxygen is diatomic => molecular mass = 2*atomic mass = 2*16)
For tri atomic molecule, d/M = 5d(oxygen)/(3*atomic mass) ---(2)
Equalizing (1) and (2), we get,
5/(3*atomic mass) = 1/32
therefore, atomic mass = 5*32/3 = 53.33 amu
For oxygen, d/M = d(oxygen)/32 ---(1)
(Oxygen is diatomic => molecular mass = 2*atomic mass = 2*16)
For tri atomic molecule, d/M = 5d(oxygen)/(3*atomic mass) ---(2)
Equalizing (1) and (2), we get,
5/(3*atomic mass) = 1/32
therefore, atomic mass = 5*32/3 = 53.33 amu
Similar questions