Question

The vapour density of a metal chloride is 100 which contains 71% chlorine by mass. The atomic mass of the metal will be:​

Answer 1

Answer:

Mass of metal chloride is equal to the mass of chlorine multiplied by factor n plus the atomic mass of metal. Let the atomic mass of metal be $x$. Then the mass of metal chloride will be $35.5n + x$.

Answer 2

Answer:

1. Mass of metal chloride is equal to the mass of chlorine multiplied by factor n plus the atomic mass of metal. Let the atomic mass of metal be $x$. Then the mass of metal chloride will be $35.5n + x$.
2. Now we know that Molecular mass of metal chloride is 100.
3. So, 35.5n+x=100
4. By putting the value of mass of metal chloride in the equation we will get the value of n as:
5. n × 35.5100=71100n=2
6. As we have calculated the value of n so putting its value in an equation in which the variables are x and n we will get the value of x as.
7. Now, we put the value of n in the last equation then we will get the value of x as:
8. 35.5×2+x=100x=29
9. By putting the value of n we get the value of x as 29. So the atomic weight of metal will be 29. And the metal chloride will be as: MCl2in which the atomic mass of M is 29

Explanation:

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