Chemistry, asked by checkoutpri9413, 1 year ago

The vapour density of a mixture containing no2 and n2o4 is 38.3 at 27º



c. The moles of no2 in 100 mole mixture is

Answers

Answered by rhansikakhandelwal10
1

hi dear

your answer is

Correct option is

A

0.437

Mol mass of mixture =2×38.3=76.6 

No. of moles in 100 g of mixture =76.6100

Let a g of NO2 is present in mixture. 

MolesofNO2+MolesofN2O4=Molesofmixture

46a+92100−a=76.6100 "or" a=20.10g

Moles of NO2 in mixture =4620.10=0.437

hopes its helps you

Answered by MRarjun77
0

From the given question, vapour density of the mixture is given which is 38.3. Solving for x we get x = 33.47 mole which gives us the number of moles of NO2 in the mixture

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