The vapour density of a mixture containing no2 and n2o4 is 38.3 at 27º
c. The moles of no2 in 100 mole mixture is
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Answered by
1
hi dear
your answer is
Correct option is
A
0.437
Mol mass of mixture =2×38.3=76.6
No. of moles in 100 g of mixture =76.6100
Let a g of NO2 is present in mixture.
MolesofNO2+MolesofN2O4=Molesofmixture
46a+92100−a=76.6100 "or" a=20.10g
Moles of NO2 in mixture =4620.10=0.437
hopes its helps you
Answered by
0
From the given question, vapour density of the mixture is given which is 38.3. Solving for x we get x = 33.47 mole which gives us the number of moles of NO2 in the mixture
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